What is the limit as x approaches infinity of e^{-2x-1} ?

The limit as x approaches infinity of e^{-2x-1} is 0

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limit as x approaches infinity of e^{-2x-1}

x \to \infty lim (e^{- 2 x - 1})

0

Solution steps

x \to \infty lim (e^{- 2 x - 1})

Apply the Limit Chain Rule:

0

= 0

x \to 0 lim (\frac{( 9 - x ) ^{- 1} - 9 ^{- 1}}{x})

x \to 0 lim (\frac{sin ( 17 x )}{x})

x \to 0 lim (\frac{( 5 ^{x} - 2 ^{x} )}{x})

x \to 0 lim (\frac{6 ^{x} - 3 ^{x}}{x})

t \to 5 lim (g (t))

What is the limit as x approaches infinity of e^{-2x-1} ?
The limit as x approaches infinity of e^{-2x-1} is 0