What is the limit as x approaches 0 of (sin(17x))/x ?

The limit as x approaches 0 of (sin(17x))/x is 17

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limit as x approaches 0 of (sin(17x))/x

x \to 0 lim (\frac{sin ( 17 x )}{x})

17

Solution steps

x \to 0 lim (\frac{sin ( 17 x )}{x})

Apply L'Hopital's Rule

= x \to 0 lim (\frac{cos ( 17 x ) \cdot 17}{1})

Plug in the value

x = 0

= \frac{cos ( 17 \cdot 0 ) \cdot 17}{1}

Simplify

\frac{cos ( 17 \cdot 0 ) \cdot 17}{1} : 17

= 17

x \to 0 lim (\frac{( 5 ^{x} - 2 ^{x} )}{x})

x \to 0 lim (\frac{6 ^{x} - 3 ^{x}}{x})

t \to 5 lim (g (t))

x \to 0 lim (∣ x ∣ sin (\frac{1}{x}))

x \to - 1 lim (1 - x)

What is the limit as x approaches 0 of (sin(17x))/x ?
The limit as x approaches 0 of (sin(17x))/x is 17