What is the limit as t approaches 0 of (2sin(4t))/t ?

The limit as t approaches 0 of (2sin(4t))/t is 8

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limit as t approaches 0 of (2sin(4t))/t

t \to 0 lim (\frac{2 sin ( 4 t )}{t})

8

Solution steps

t \to 0 lim (\frac{2 sin ( 4 t )}{t})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 2 \cdot t \to 0 lim (\frac{sin ( 4 t )}{t})

Apply L'Hopital's Rule

= 2 \cdot t \to 0 lim (\frac{cos ( 4 t ) \cdot 4}{1})

Plug in the value

t = 0

= 2 \cdot \frac{cos ( 4 \cdot 0 ) \cdot 4}{1}

Simplify

2 \cdot \frac{cos ( 4 \cdot 0 ) \cdot 4}{1} : 8

= 8

x \to \infty lim (3 x^{2} - 1)

x \to 4 lim (5 x - 7)

x \to 0 + lim ((x - 2)^{5})

x \to \infty lim (3 x^{2} - x)

x \to 0 + lim (cos (x) \cdot ln (x))

What is the limit as t approaches 0 of (2sin(4t))/t ?
The limit as t approaches 0 of (2sin(4t))/t is 8