What is the integral of 8te^t ?

The integral of 8te^t is 8(e^tt-e^t)+C

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integral of 8te^t

\int 8 t e^{t} d t

8 (e^{t} t - e^{t}) + C

Solution steps

\int 8 t e^{t} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int t e^{t} d t

Apply Integration By Parts

= 8 (e^{t} t - \int e^{t} d t)

\int e^{t} d t = e^{t}

= 8 (e^{t} t - e^{t})

Add a constant to the solution

= 8 (e^{t} t - e^{t}) + C

\frac{d}{d x} (2 csc (2 x))

l a pl a ce t r an s f or m 8 t^{2}

y^{^{'}} + 2 y = 60, y (1) = 80

d er i v a t i v e f (x) = 3 sin (x) + cos (x)

\int (3 x^{2} + 2 x) ln (x) d x