What is laplacetransform 8t^2 ?

The answer to laplacetransform 8t^2 is (16)/(s^3)

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laplacetransform 8t^2

laplace transform

8 t^{2}

\frac{16}{s ^{3}}

Solution steps

L {8 t^{2}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 8 L {t^{2}}

L {t^{2}} : \frac{2}{s ^{3}}

= 8 \cdot \frac{2}{s ^{3}}

Refine

8 \frac{2}{s ^{3}} : \frac{16}{s ^{3}}

= \frac{16}{s ^{3}}

y^{^{'}} + 2 y = 60, y (1) = 80

d er i v a t i v e f (x) = 3 sin (x) + cos (x)

\int (3 x^{2} + 2 x) ln (x) d x

\frac{d}{d x} ((1 + sin (3 x))^{4})

\frac{d}{d x} ((3 cos (2 x) + sin (3 x) + 4)^{2})

What is laplacetransform 8t^2 ?
The answer to laplacetransform 8t^2 is (16)/(s^3)