integral from-1 to 3 of (x-1)

Lösung

\int_{- 1}^{3} (x - 1) d x

0

Schritte zur Lösung

\int_{- 1}^{3} x - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{3} x d x - \int_{- 1}^{3} 1 d x

\int_{- 1}^{3} x d x = 4

\int_{- 1}^{3} 1 d x = 4

= 4 - 4

Vereinfache

= 0

\int_{1}^{e^{2}} ln (x) d x

\int_{- 5}^{0} x^{3} d x

\int_{0}^{4} (3 x^{2} + x - 8) d x

\int_{1}^{4} x^{3} d x

\int_{3}^{9} 1 + 3 x d x