integral from 3 to 9 of sqrt(1+3x)

Lösung

\int_{3}^{9} 1 + 3 x d x

\frac{112 7 - 20 10}{9}

Dezimale

25.89762 \dots

Schritte zur Lösung

\int_{3}^{9} 1 + 3 x d x

Wende U-Substitution an

= \int_{10}^{28} \frac{u}{3} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int_{10}^{28} u d u

Wende die Potenzregel an

= \frac{1}{3} [\frac{2}{3} u^{\frac{3}{2}}]_{10}^{28}

Berechne die Grenzen:

\frac{112 7 - 20 10}{3}

= \frac{1}{3} \cdot \frac{112 7 - 20 10}{3}

Vereinfache

= \frac{112 7 - 20 10}{9}

\int_{0}^{5} \frac{1}{1 + x ^{2} + y ^{2}} d z

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