What is the integral from a to b of x^{-2} ?

The integral from a to b of x^{-2} is -1/b+1/a

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from a to b of x^{-2}

\int_{a}^{b} x^{- 2} d x

- \frac{1}{b} + \frac{1}{a}

Solution steps

\int_{a}^{b} x^{- 2} d x

Apply the Power Rule

: [- \frac{1}{x}]_{a}^{b}

= [- \frac{1}{x}]_{a}^{b}

Compute the boundaries:

- \frac{1}{b} + \frac{1}{a}

= - \frac{1}{b} + \frac{1}{a}

\int_{- 7}^{7} \frac{1}{x ^{2}} d x

\int_{0}^{1} (2 t + 1) (e^{- s t}) d t

\int_{2}^{3} \frac{x - 1}{x ^{2}} e^{x} d x

\int_{0}^{5} \frac{e ^{x}}{5 + e ^{x}} d x

\int_{1}^{2} (x + 2 y)^{- 2} d x

What is the integral from a to b of x^{-2} ?
The integral from a to b of x^{-2} is -1/b+1/a