What is the integral from-7 to 7 of 1/(x^2) ?

The integral from-7 to 7 of 1/(x^2) is diverges

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integral from-7 to 7 of 1/(x^2)

\int_{- 7}^{7} \frac{1}{x ^{2}} d x

diverges

Solution steps

\int_{- 7}^{7} \frac{1}{x ^{2}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 7}^{0} \frac{1}{x ^{2}} d x + \int_{0}^{7} \frac{1}{x ^{2}} d x

\int_{- 7}^{0} \frac{1}{x ^{2}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

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\int_{1}^{2} (x + 2 y)^{- 2} d x

\int_{3}^{5} x^{2} - 4 x d x

What is the integral from-7 to 7 of 1/(x^2) ?
The integral from-7 to 7 of 1/(x^2) is diverges