integral from 0 to 1 of (5x^2-8x+4)

Lösung

\int_{0}^{1} (5 x^{2} - 8 x + 4) d x

\frac{5}{3}

Dezimale

1.66666 \dots

Schritte zur Lösung

\int_{0}^{1} 5 x^{2} - 8 x + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 5 x^{2} d x - \int_{0}^{1} 8 x d x + \int_{0}^{1} 4 d x

\int_{0}^{1} 5 x^{2} d x = \frac{5}{3}

\int_{0}^{1} 8 x d x = 4

\int_{0}^{1} 4 d x = 4

= \frac{5}{3} - 4 + 4

Vereinfache

= \frac{5}{3}

\int_{1}^{3} (x^{2} - 4 x + 8) d x

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