integral from 0 to 1 of (-x)

Lösung

\int_{0}^{1} (- x) d x

- \frac{1}{2}

Dezimale

- 0.5

Schritte zur Lösung

\int_{0}^{1} - x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{1} x d x

Wende die Potenzregel an

= - [\frac{x ^{2}}{2}]_{0}^{1}

Berechne die Grenzen:

\frac{1}{2}

= - \frac{1}{2}

\int_{0}^{\frac{π}{2}} x sin^{2} (\frac{x}{2}) d x

\int_{0}^{4 π} sin^{2} (x) d x

\int_{0}^{\infty} \frac{3}{x ^{2}} d x

\int_{2}^{\infty} \frac{3}{x ^{2}} d x

\int_{0}^{x} \frac{x ^{2}}{2} d x