What is the integral from 0 to 3t of (sin(u))/u ?

The integral from 0 to 3t of (sin(u))/u is \Si(3t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 3t of (sin(u))/u

\int_{0}^{3 t} \frac{sin ( u )}{u} d u

Si (3 t)

Solution steps

\int_{0}^{3 t} \frac{sin ( u )}{u} d u

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (u)]_{0}^{3 t}

Compute the boundaries:

Si (3 t)

= Si (3 t)

\int_{0}^{\infty} x \cdot e^{x} d x

\int_{0}^{π} x sin (k x) d x

\int_{0}^{y} \frac{2 x ^{2}}{y ^{2}} d x

\int_{\frac{1}{6}}^{e} ∣ ln (x) ∣ d x

\int_{0}^{2 π} cos (x) + 1 d x

What is the integral from 0 to 3t of (sin(u))/u ?
The integral from 0 to 3t of (sin(u))/u is \Si(3t)