What is the integral from 1/6 to e of |ln(x)| ?

The integral from 1/6 to e of |ln(x)| is 11/6-1/6 ln(6)

integral from 1/6 to e of |ln(x)|

\int_{\frac{1}{6}}^{e} ∣ ln (x) ∣ d x

\frac{11}{6} - \frac{1}{6} ln (6)

Decimal

1.53470 \dots

Solution steps

\int_{\frac{1}{6}}^{e} ∣ ln (x) ∣ d x

Apply u-substitution

= \int_{- l n (6)}^{1} ∣ u ∣ e^{u} d u

Eliminate Absolutes

= \int_{- l n (6)}^{0} (- u) e^{u} d u + \int_{0}^{1} u e^{u} d u

\int_{- l n (6)}^{0} (- u) e^{u} d u = \frac{5}{6} - \frac{1}{6} ln (6)

\int_{0}^{1} u e^{u} d u = 1

= \frac{5}{6} - \frac{1}{6} ln (6) + 1

Combine the fractions

1 + \frac{5}{6} : \frac{11}{6}

= \frac{11}{6} - \frac{1}{6} ln (6)

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What is the integral from 1/6 to e of |ln(x)| ?
The integral from 1/6 to e of |ln(x)| is 11/6-1/6 ln(6)