What is the integral from-3 to 2 of x^3+x^2-6x ?

The integral from-3 to 2 of x^3+x^2-6x is 125/12

integral from-3 to 2 of x^3+x^2-6x

\int_{- 3}^{2} x^{3} + x^{2} - 6 x d x

\frac{125}{12}

Decimal

10.41666 \dots

Solution steps

\int_{- 3}^{2} x^{3} + x^{2} - 6 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 3}^{2} x^{3} d x + \int_{- 3}^{2} x^{2} d x - \int_{- 3}^{2} 6 x d x

\int_{- 3}^{2} x^{3} d x = - \frac{65}{4}

\int_{- 3}^{2} x^{2} d x = \frac{35}{3}

\int_{- 3}^{2} 6 x d x = - 15

= - \frac{65}{4} + \frac{35}{3} - (- 15)

Simplify

- \frac{65}{4} + \frac{35}{3} - (- 15) : \frac{125}{12}

= \frac{125}{12}

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What is the integral from-3 to 2 of x^3+x^2-6x ?
The integral from-3 to 2 of x^3+x^2-6x is 125/12