integral from 0 to 2 of sqrt(4+x)

Lösung

\int_{0}^{2} 4 + x d x

46 - \frac{16}{3}

Dezimale

4.46462 \dots

Schritte zur Lösung

\int_{0}^{2} 4 + x d x

Wende U-Substitution an

= \int_{4}^{6} u d u

Wende die Potenzregel an

= [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{6}

Berechne die Grenzen:

46 - \frac{16}{3}

= 46 - \frac{16}{3}

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