integral from-1 to 2 of (2+|x|)

Lösung

\int_{- 1}^{2} (2 + ∣ x ∣) d x

\frac{17}{2}

Dezimale

8.5

Schritte zur Lösung

\int_{- 1}^{2} 2 + ∣ x ∣ d x

Entferne die Extremwerte

= \int_{- 1}^{0} 2 - x d x + \int_{0}^{2} 2 + x d x

\int_{- 1}^{0} 2 - x d x = \frac{5}{2}

\int_{0}^{2} 2 + x d x = 6

= \frac{5}{2} + 6

Vereinfache

\frac{5}{2} + 6 : \frac{17}{2}

= \frac{17}{2}

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