integral from 0 to 5 of (2x+3)

Lösung

\int_{0}^{5} (2 x + 3) d x

40

Schritte zur Lösung

\int_{0}^{5} 2 x + 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{5} 2 x d x + \int_{0}^{5} 3 d x

\int_{0}^{5} 2 x d x = 25

\int_{0}^{5} 3 d x = 15

= 25 + 15

Vereinfache

= 40

\int_{0}^{1} 16 t^{3} d t

\int_{\frac{1}{3}}^{3} (3 - \frac{3}{x ^{2}}) d x

\int_{- 2}^{2} 3 x^{8} - 2 d x

\int_{- 3}^{0} (x + 3)^{2} d x

\int_{0}^{2} x f (x^{2}) d x