integral from 0 to 1 of 16t^3

Lösung

\int_{0}^{1} 16 t^{3} d t

4

Schritte zur Lösung

\int_{0}^{1} 16 t^{3} d t

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 16 \cdot \int_{0}^{1} t^{3} d t

Wende die Potenzregel an

= 16 [\frac{t ^{4}}{4}]_{0}^{1}

Berechne die Grenzen:

\frac{1}{4}

= 16 \cdot \frac{1}{4}

Vereinfache

= 4

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