integral from 6 to 9 of (1/(x^2))

Lösung

\int_{6}^{9} (\frac{1}{x ^{2}}) d x

\frac{1}{18}

Dezimale

0.05555 \dots

Schritte zur Lösung

\int_{6}^{9} \frac{1}{x ^{2}} d x

Wende die Potenzregel an

= [- \frac{1}{x}]_{6}^{9}

Berechne die Grenzen:

\frac{1}{18}

= \frac{1}{18}

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