What is the integral from 0 to 2pi of 3cos(t) ?

The integral from 0 to 2pi of 3cos(t) is 0

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integral from 0 to 2pi of 3cos(t)

\int_{0}^{2 π} 3 cos (t) d t

0

Solution steps

\int_{0}^{2 π} 3 cos (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{2 π} cos (t) d t

Use the common integral:

\int cos (t) d t = sin (t)

= 3 [sin (t)]_{0}^{2 π}

Compute the boundaries:

0

= 3 \cdot 0

Simplify

= 0

\int_{- 1}^{1} 2 x^{2} + \frac{2}{3} d x

\int_{- 1}^{0} (x^{\frac{1}{3}} - x) d x

\int_{0}^{π} y sin (x) d x

\int_{- 1}^{2} x (\frac{x ^{2}}{3}) d x

\int_{- 1}^{1} \frac{x}{x + 2} d x

What is the integral from 0 to 2pi of 3cos(t) ?
The integral from 0 to 2pi of 3cos(t) is 0