integral from-1 to 1 of x/(x+2)

Lösung

\int_{- 1}^{1} \frac{x}{x + 2} d x

2 - 2 ln (3)

Dezimale

- 0.19722 \dots

Schritte zur Lösung

\int_{- 1}^{1} \frac{x}{x + 2} d x

Wende U-Substitution an

= \int_{1}^{3} \frac{u - 2}{u} d u

Multipliziere aus

\frac{u - 2}{u} : 1 - \frac{2}{u}

= \int_{1}^{3} 1 - \frac{2}{u} d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 1 d u - \int_{1}^{3} \frac{2}{u} d u

\int_{1}^{3} 1 d u = 2

\int_{1}^{3} \frac{2}{u} d u = 2 ln (3)

= 2 - 2 ln (3)

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