integral from 0 to pi/3 of sin(θ)

Lösung

\int_{0}^{\frac{π}{3}} sin (θ) d θ

\frac{1}{2}

Dezimale

0.5

Schritte zur Lösung

\int_{0}^{\frac{π}{3}} sin (θ) d θ

Nutze das gemeinsame Integral :

\int sin (θ) d θ = - cos (θ)

= [- cos (θ)]_{0}^{\frac{π}{3}}

Berechne die Grenzen:

\frac{1}{2}

= \frac{1}{2}

\int_{0}^{b} π x^{2} d x

\int_{0}^{π} 1 + x^{2} d x

\int_{3}^{6} - 5 x + 6 d x

\int_{1}^{7} \frac{1}{5 x} d x

\int_{\frac{π}{6}}^{\frac{π}{3}} sin (θ) d θ