integral from 0 to y of 2xyz

Lösung

\int_{0}^{y} 2 x yz d z

x y^{3}

Schritte zur Lösung

\int_{0}^{y} 2 x yz d z

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 x y \cdot \int_{0}^{y} z d z

Wende die Potenzregel an

= 2 x y [\frac{z ^{2}}{2}]_{0}^{y}

Berechne die Grenzen:

\frac{y ^{2}}{2}

= 2 x y \frac{y ^{2}}{2}

Vereinfache

= x y^{3}

\int_{0}^{1} e^{- i wt} d t

\int_{0}^{2} \frac{1}{( 2 - x ) ^{\frac{4}{5}}} d x

\int_{0}^{1} 1 + x^{2} x d x

\int_{0}^{2 x} sin (t^{2}) d t

\int_{0}^{x} y e^{- y x} d x