integral from 0 to 1 of y^3-y

Lösung

\int_{0}^{1} y^{3} - y d y

- \frac{1}{4}

Dezimale

- 0.25

Schritte zur Lösung

\int_{0}^{1} y^{3} - y d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} y^{3} d y - \int_{0}^{1} y d y

\int_{0}^{1} y^{3} d y = \frac{1}{4}

\int_{0}^{1} y d y = \frac{1}{2}

= \frac{1}{4} - \frac{1}{2}

Vereinfache

\frac{1}{4} - \frac{1}{2} : - \frac{1}{4}

= - \frac{1}{4}

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