integral from 2 to 7 of e^{2-x}

Lösung

\int_{2}^{7} e^{2 - x} d x

1 - \frac{1}{e ^{5}}

Dezimale

0.99326 \dots

Schritte zur Lösung

\int_{2}^{7} e^{2 - x} d x

Wende U-Substitution an

= \int_{0}^{- 5} - e^{u} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 5}^{0} - e^{u} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int_{- 5}^{0} e^{u} d u)

Nutze das gemeinsame Integral :

\int e^{u} d u = e^{u}

= - (- [e^{u}]_{- 5}^{0})

Vereinfache

= [e^{u}]_{- 5}^{0}

Berechne die Grenzen:

1 - \frac{1}{e ^{5}}

= 1 - \frac{1}{e ^{5}}

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