integral from 0 to pi/(12) of cos(6t)

Lösung

\int_{0}^{\frac{π}{12}} cos (6 t) d t

\frac{1}{6}

Dezimale

0.16666 \dots

Schritte zur Lösung

\int_{0}^{\frac{π}{12}} cos (6 t) d t

Wende U-Substitution an

= \int_{0}^{\frac{π}{2}} cos (u) \frac{1}{6} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int_{0}^{\frac{π}{2}} cos (u) d u

Nutze das gemeinsame Integral :

\int cos (u) d u = sin (u)

= \frac{1}{6} [sin (u)]_{0}^{\frac{π}{2}}

Berechne die Grenzen:

1

= \frac{1}{6} \cdot 1

Vereinfache

= \frac{1}{6}

\int_{1}^{2} e^{x} + \frac{1}{x} d x

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