integral from-1 to 3 of (2x^2-4x)

Lösung

\int_{- 1}^{3} (2 x^{2} - 4 x) d x

\frac{8}{3}

Dezimale

2.66666 \dots

Schritte zur Lösung

\int_{- 1}^{3} 2 x^{2} - 4 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{3} 2 x^{2} d x - \int_{- 1}^{3} 4 x d x

\int_{- 1}^{3} 2 x^{2} d x = \frac{56}{3}

\int_{- 1}^{3} 4 x d x = 16

= \frac{56}{3} - 16

Vereinfache

\frac{56}{3} - 16 : \frac{8}{3}

= \frac{8}{3}

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