integral from 4.2 to 9.9 of 12x^2-6x+4/x

Lösung

\int_{4.2}^{9.9} 12 x^{2} - 6 x + \frac{4}{x} d x

3347.16380 \dots

Schritte zur Lösung

\int_{4.2}^{9.9} 12 x^{2} - 6 x + \frac{4}{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{4.2}^{9.9} 12 x^{2} d x - \int_{4.2}^{9.9} 6 x d x + \int_{4.2}^{9.9} \frac{4}{x} d x

\int_{4.2}^{9.9} 12 x^{2} d x = 3584.844

\int_{4.2}^{9.9} 6 x d x = 241.11

\int_{4.2}^{9.9} \frac{4}{x} d x = 3.42980 \dots

= 3584.844 - 241.11 + 3.42980 \dots

Vereinfache

= 3347.16380 \dots

\int_{0}^{1} (5 x^{2} - 4 x + 7) d x

\int_{5}^{1} x^{2} x - 1 d x

\int_{- 6}^{2} x - 12 - 4 x d x

\int_{0.5}^{0.75} 12 x^{2} d x

\int_{1}^{3} \frac{3}{7 x - 2} d x