integral from 0.5 to 0.75 of 12x^2

Lösung

\int_{0.5}^{0.75} 12 x^{2} d x

1.1875

Schritte zur Lösung

\int_{0.5}^{0.75} 12 x^{2} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 12 \cdot \int_{0.5}^{0.75} x^{2} d x

Wende die Potenzregel an

= 12 [\frac{x ^{3}}{3}]_{0.5}^{0.75}

Vereinfache

= 12 [0.33333 \dots x^{3}]_{0.5}^{0.75}

Berechne die Grenzen:

0.09895 \dots

= 12 \cdot 0.09895 \dots

Vereinfache

= 1.1875

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