integral from 1 to 5 of 6x

Lösung

\int_{1}^{5} 6 x d x

72

Schritte zur Lösung

\int_{1}^{5} 6 x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{1}^{5} x d x

Wende die Potenzregel an

= 6 [\frac{x ^{2}}{2}]_{1}^{5}

Berechne die Grenzen:

12

= 6 \cdot 12

Vereinfache

= 72

\int_{0}^{2} x sin (n x) d x

\int_{4.2}^{9.9} 12 x^{2} - 6 x + \frac{4}{x} d x

\int_{0}^{1} (5 x^{2} - 4 x + 7) d x

\int_{5}^{1} x^{2} x - 1 d x

\int_{- 6}^{2} x - 12 - 4 x d x