integral from 1 to 3 of (z^2+2)/z

Lösung

\int_{1}^{3} \frac{z ^{2} + 2}{z} d z

4 + 2 ln (3)

Dezimale

6.19722 \dots

Schritte zur Lösung

\int_{1}^{3} \frac{z ^{2} + 2}{z} d z

Multipliziere aus

\frac{z ^{2} + 2}{z} : z + \frac{2}{z}

= \int_{1}^{3} z + \frac{2}{z} d z

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} z d z + \int_{1}^{3} \frac{2}{z} d z

\int_{1}^{3} z d z = 4

\int_{1}^{3} \frac{2}{z} d z = 2 ln (3)

= 4 + 2 ln (3)

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