integral from 0 to y/3 of (y^2-9x^2)/2

Lösung

\int_{0}^{\frac{y}{3}} \frac{y ^{2} - 9 x ^{2}}{2} d x

\frac{y ^{3}}{9}

Schritte zur Lösung

\int_{0}^{\frac{y}{3}} \frac{y ^{2} - 9 x ^{2}}{2} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{\frac{y}{3}} y^{2} - 9 x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int_{0}^{\frac{y}{3}} y^{2} d x - \int_{0}^{\frac{y}{3}} 9 x^{2} d x)

\int_{0}^{\frac{y}{3}} y^{2} d x = \frac{y ^{3}}{3}

\int_{0}^{\frac{y}{3}} 9 x^{2} d x = \frac{y ^{3}}{9}

= \frac{1}{2} (\frac{y ^{3}}{3} - \frac{y ^{3}}{9})

Vereinfache

\frac{1}{2} (\frac{y ^{3}}{3} - \frac{y ^{3}}{9}) : \frac{y ^{3}}{9}

= \frac{y ^{3}}{9}

\int_{2}^{4} \frac{2}{x ^{2} + x - 2} d x

\int_{0}^{9} (9 x - x^{2}) d x

\int_{1}^{4} cos (x) - \frac{3}{x ^{5}} d x

\int_{1}^{\infty} 6 e^{- 6 x} d x

\int_{1}^{9} \frac{5}{x} d x