integral from 0 to 9 of (9x-x^2)

Lösung

\int_{0}^{9} (9 x - x^{2}) d x

\frac{243}{2}

Dezimale

121.5

Schritte zur Lösung

\int_{0}^{9} 9 x - x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{9} 9 x d x - \int_{0}^{9} x^{2} d x

\int_{0}^{9} 9 x d x = \frac{729}{2}

\int_{0}^{9} x^{2} d x = 243

= \frac{729}{2} - 243

Vereinfache

\frac{729}{2} - 243 : \frac{243}{2}

= \frac{243}{2}

\int_{1}^{4} cos (x) - \frac{3}{x ^{5}} d x

\int_{1}^{\infty} 6 e^{- 6 x} d x

\int_{1}^{9} \frac{5}{x} d x

\int_{5}^{7} \frac{1}{x - 4} d x

\int_{- 2}^{0} 3 x d x