integral from 0 to 4 of (2x+1)

Lösung

\int_{0}^{4} (2 x + 1) d x

20

Schritte zur Lösung

\int_{0}^{4} 2 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 2 x d x + \int_{0}^{4} 1 d x

\int_{0}^{4} 2 x d x = 16

\int_{0}^{4} 1 d x = 4

= 16 + 4

Vereinfache

= 20

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