integral from 0 to pi/4 of 4sin(x)cos(x)

Lösung

\int_{0}^{\frac{π}{4}} 4 sin (x) cos (x) d x

1

Schritte zur Lösung

\int_{0}^{\frac{π}{4}} 4 sin (x) cos (x) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{\frac{π}{4}} sin (x) cos (x) d x

Wende U-Substitution an

= 4 \cdot \int_{0}^{\frac{2}{2}} u d u

Wende die Potenzregel an

= 4 [\frac{u ^{2}}{2}]_{0}^{\frac{2}{2}}

\frac{2}{2} = \frac{1}{2}

= 4 [\frac{u ^{2}}{2}]_{0}^{\frac{1}{2}}

Berechne die Grenzen:

\frac{1}{4}

= 4 \cdot \frac{1}{4}

Vereinfache

= 1

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