integral from-1 to 1 of 4x^2+3

Lösung

\int_{- 1}^{1} 4 x^{2} + 3 d x

\frac{26}{3}

Dezimale

8.66666 \dots

Schritte zur Lösung

\int_{- 1}^{1} 4 x^{2} + 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 4 x^{2} d x + \int_{- 1}^{1} 3 d x

\int_{- 1}^{1} 4 x^{2} d x = \frac{8}{3}

\int_{- 1}^{1} 3 d x = 6

= \frac{8}{3} + 6

Vereinfache

\frac{8}{3} + 6 : \frac{26}{3}

= \frac{26}{3}

\int_{0}^{5} (4 x - 1)^{2} d x

\int_{2}^{10} \frac{x}{2} - \frac{2}{x} d x

\int_{- 1}^{x} \frac{3}{2} x^{2} d x

\int_{0}^{2 π} (sin^{2} (t)) d t

\int_{- 1}^{2} (x + 2) d x