integral from-1 to 2 of (x+2)

Lösung

\int_{- 1}^{2} (x + 2) d x

\frac{15}{2}

Dezimale

7.5

Schritte zur Lösung

\int_{- 1}^{2} x + 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x d x + \int_{- 1}^{2} 2 d x

\int_{- 1}^{2} x d x = \frac{3}{2}

\int_{- 1}^{2} 2 d x = 6

= \frac{3}{2} + 6

Vereinfache

\frac{3}{2} + 6 : \frac{15}{2}

= \frac{15}{2}

\int_{- \frac{π}{2}}^{\frac{π}{2}} 3 cos^{3} (x) d x

\int_{0}^{1} \frac{10}{t ^{2} + 1} d t

\int_{0}^{t} \frac{1}{t + 10} d t

\int_{0}^{1} 4 x^{3} (3 x^{4} - 3)^{5} d x

\int_{0}^{1} (x + 3)^{3} d x