integral from 0 to 4 of 1/(sqrt(1+2x))

Lösung

\int_{0}^{4} \frac{1}{1 + 2 x} d x

2

Schritte zur Lösung

\int_{0}^{4} \frac{1}{1 + 2 x} d x

Wende U-Substitution an

= \int_{1}^{3} 1 d u

Integral einer Konstanten :

\int a d x = a x

= [1 \cdot u]_{1}^{3}

Vereinfache

= [u]_{1}^{3}

Berechne die Grenzen:

2

= 2

\int_{3}^{\infty} 2 e^{- s t} d t

\int_{0}^{1} 2 t^{3} d t

\int_{0}^{\infty} e^{- y} y^{2} d y

\int_{1}^{2} \frac{2 + 3 x}{x} d x

\int_{- 1}^{1} \frac{4 x}{x ^{2} + 3} d x