integral from 1 to 2 of (x^3+1)

Lösung

\int_{1}^{2} (x^{3} + 1) d x

\frac{19}{4}

Dezimale

4.75

Schritte zur Lösung

\int_{1}^{2} x^{3} + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{3} d x + \int_{1}^{2} 1 d x

\int_{1}^{2} x^{3} d x = \frac{15}{4}

\int_{1}^{2} 1 d x = 1

= \frac{15}{4} + 1

Vereinfache

\frac{15}{4} + 1 : \frac{19}{4}

= \frac{19}{4}

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