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Popular Calculus >

integral from 0 to 1 of (e^x+1)

Solution

\int_{0}^{1} (e^{x} + 1) d x

Solution

e

+1

Decimal

2.71828 \dots

Solution steps

\int_{0}^{1} e^{x} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} e^{x} d x + \int_{0}^{1} 1 d x

\int_{0}^{1} e^{x} d x = e - 1

\int_{0}^{1} 1 d x = 1

= e - 1 + 1

Simplify

= e

Graph

Popular Examples

integral from 2 to 5 of (6+cos(x/(10)))

\int_{2}^{5} (6 + cos (\frac{x}{10})) d x

integral from 0 to 1 of 2x^3

\int_{0}^{1} 2 x^{3} d x

integral from 2 to 4 of |x^2-2x-3|

\int_{2}^{4} x^{2} - 2 x - 3 d x

integral from 0 to pi/2 of x

\int_{0}^{\frac{π}{2}} x d x

integral from-1 to 2 of 2x

\int_{- 1}^{2} 2 x d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (e^x+1) ?
The integral from 0 to 1 of (e^x+1) is e