What is the integral from 2 to 4 of |x^2-2x-3| ?

The integral from 2 to 4 of |x^2-2x-3| is 4

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integral from 2 to 4 of |x^2-2x-3|

\int_{2}^{4} x^{2} - 2 x - 3 d x

4

Solution steps

\int_{2}^{4} x^{2} - 2 x - 3 d x

Eliminate Absolutes

= \int_{2}^{3} - x^{2} + 2 x + 3 d x + \int_{3}^{4} x^{2} - 2 x - 3 d x

\int_{2}^{3} - x^{2} + 2 x + 3 d x = \frac{5}{3}

\int_{3}^{4} x^{2} - 2 x - 3 d x = \frac{7}{3}

= \frac{5}{3} + \frac{7}{3}

Simplify

\frac{5}{3} + \frac{7}{3} : 4

= 4

\int_{0}^{\frac{π}{2}} x d x

\int_{- 1}^{2} 2 x d x

\int_{1}^{\infty} x^{2} e^{- x} d x

\int_{- 2}^{3} e^{\frac{x}{2}} d x

\int_{0}^{1} x ln (1 + x) d x

What is the integral from 2 to 4 of |x^2-2x-3| ?
The integral from 2 to 4 of |x^2-2x-3| is 4