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受欢迎的微积分 >

integral of (sqrt(x+1))/(2x+3)

解答

\int \frac{x + 1}{2 x + 3} d x

解答

\frac{1}{2} (- arctan (2 x + 2) + 2 x + 2) + C

求解步骤

\int \frac{x + 1}{2 x + 3} d x

使用换元积分法

= \int \frac{u - 1}{2 2 u} d u

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2 2} \cdot \int \frac{u - 1}{u} d u

使用换元积分法

= \frac{1}{2 2} \cdot \int \frac{2 v ^{2}}{v ^{2} + 1} d v

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2 2} \cdot 2 \cdot \int \frac{v ^{2}}{v ^{2} + 1} d v

\frac{v ^{2}}{v ^{2} + 1} = - \frac{1}{v ^{2} + 1} + 1

= \frac{1}{2 2} \cdot 2 \cdot \int - \frac{1}{v ^{2} + 1} + 1 d v

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2 2} \cdot 2 (- \int \frac{1}{v ^{2} + 1} d v + \int 1 d v)

\int \frac{1}{v ^{2} + 1} d v = arctan (v)

\int 1 d v = v

= \frac{1}{2 2} \cdot 2 (- arctan (v) + v)

代回

= \frac{1}{2 2} \cdot 2 (- arctan (2 x + 3 - 1) + 2 x + 3 - 1)

化简

\frac{1}{2 2} \cdot 2 (- arctan (2 x + 3 - 1) + 2 x + 3 - 1) : \frac{1}{2} (- arctan (2 x + 2) + 2 x + 2)

= \frac{1}{2} (- arctan (2 x + 2) + 2 x + 2)

解答补常数

= \frac{1}{2} (- arctan (2 x + 2) + 2 x + 2) + C

作图

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