What is the integral of (x^{-5/4}) ?

The integral of (x^{-5/4}) is -4/(x^{1/4)}+C

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integral of (x^{-5/4})

\int (x^{- \frac{5}{4}}) d x

- \frac{4}{x ^{\frac{1}{4}}} + C

Solution steps

\int x^{- \frac{5}{4}} d x

Apply the Power Rule

= - \frac{4}{x ^{\frac{1}{4}}}

Add a constant to the solution

= - \frac{4}{x ^{\frac{1}{4}}} + C

\int s \cdot 2^{s} d s

\int \frac{y ^{3}}{( 2 + y ^{2} ) ^{\frac{5}{2}}} d y

\int \frac{x}{1 + x x} d x

\int \frac{x ^{2} + 2}{( x + 1 ) ( x ^{2} + 4 )} d x

\int u^{\frac{- 1}{2}} d u

What is the integral of (x^{-5/4}) ?
The integral of (x^{-5/4}) is -4/(x^{1/4)}+C