limit as θ approaches+0 of (tan(2θ))/θ

Lösung

θ \to + 0 lim (\frac{tan ( 2 θ )}{θ})

2

Schritte zur Lösung

θ \to 0 lim (\frac{tan ( 2 θ )}{θ})

Wende das L'Hopital Theorem an

= θ \to 0 lim (\frac{sec ^{2} ( 2 θ ) \cdot 2}{1})

Setze den Wert

θ = 0

ein

= \frac{sec ^{2} ( 2 \cdot 0 ) \cdot 2}{1}

Vereinfache

\frac{sec ^{2} ( 2 \cdot 0 ) \cdot 2}{1} : 2

= 2

x \to 3 + lim (\frac{x - 3}{x - 2 - 4 - x})

n = 1 \sum \infty i^{2 n}

n = 2 \sum \infty n (\frac{3}{4})^{n}

x \to 1 lim (\frac{x}{x - 1})

x \to 7 lim (x + 2 - 3)