What is the integral of 6-sqrt(x) ?

The integral of 6-sqrt(x) is 6x-2/3 x^{3/2}+C

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integral of 6-sqrt(x)

\int 6 - x d x

6 x - \frac{2}{3} x^{\frac{3}{2}} + C

Solution steps

\int 6 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 6 d x - \int x d x

\int 6 d x = 6 x

\int x d x = \frac{2}{3} x^{\frac{3}{2}}

= 6 x - \frac{2}{3} x^{\frac{3}{2}}

Add a constant to the solution

= 6 x - \frac{2}{3} x^{\frac{3}{2}} + C

\int x (x + 4) (2 x - 1) d x

\int \frac{1}{( x ln ( x ) )} d x

in t e g r a l sin (3 x)

\int \frac{( 2 x + 3 )}{x ^{2} + 2 x + 5} d x

\int (\frac{3 x ^{2} + 6 x + 1}{x}) d x

What is the integral of 6-sqrt(x) ?
The integral of 6-sqrt(x) is 6x-2/3 x^{3/2}+C