limit as x approaches pi of (sin(x))/(1-\frac{x^2){pi^2}}

Lösung

x \to π lim (\frac{sin ( x )}{1 - \frac{x ^{2}}{π ^{2}}})

\frac{π}{2}

Dezimale

1.57079 \dots

Schritte zur Lösung

x \to π lim (\frac{sin ( x )}{1 - \frac{x ^{2}}{π ^{2}}})

Wende das L'Hopital Theorem an

= x \to π lim (\frac{cos ( x )}{- \frac{2 x}{π ^{2}}})

Setze den Wert

x = π

ein

= \frac{cos ( π )}{- \frac{2 π}{π ^{2}}}

Vereinfache

\frac{cos ( π )}{- \frac{2 π}{π ^{2}}} : \frac{π}{2}

= \frac{π}{2}

x \to \infty lim (9 x^{2} e^{- x})

(\frac{x ^{3}}{6} + \frac{1}{2 x})^{^{'}}

\int_{6}^{\infty} \frac{1}{( x - 5 ) ^{\frac{3}{2}}} d x

\int_{0}^{5} x^{2} + 25 d x

d er i v a t i v e y = sin (x y)