What is the integral from-5 to 5 of y/(sqrt(25-y^2)) ?

The integral from-5 to 5 of y/(sqrt(25-y^2)) is 0

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integral from-5 to 5 of y/(sqrt(25-y^2))

\int_{- 5}^{5} \frac{y}{25 - y ^{2}} d y

0

Solution steps

\int_{- 5}^{5} \frac{y}{25 - y ^{2}} d y

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{y}{25 - y ^{2}} :

Odd

= 0

d er i v a t i v e x^{3} (2 x - 1)^{7}

x \to 0 lim (x + 2)

\frac{d}{d x} (sin (x + 3) + (- cos (x - \frac{1}{2})))

\frac{d}{d x} (\frac{x ^{2} + x}{x + 1})

\frac{d}{d x} (\frac{x ^{2} + 2}{x ^{4} - 3 x ^{2} + 1})

What is the integral from-5 to 5 of y/(sqrt(25-y^2)) ?
The integral from-5 to 5 of y/(sqrt(25-y^2)) is 0