What is the integral of 2e^xx ?

The integral of 2e^xx is 2(e^xx-e^x)+C

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integral of 2e^xx

\int 2 e^{x} x d x

2 (e^{x} x - e^{x}) + C

Solution steps

\int 2 e^{x} x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int e^{x} x d x

Apply Integration By Parts

= 2 (e^{x} x - \int e^{x} d x)

\int e^{x} d x = e^{x}

= 2 (e^{x} x - e^{x})

Add a constant to the solution

= 2 (e^{x} x - e^{x}) + C

d er i v a t i v e y = ln (x^{5})

\frac{d}{d x} (- \frac{3}{x ^{2}} + 4 e^{2 x})

f (x) = \frac{x ^{2}}{3}

\frac{\partial}{\partial y} (2 x + 3 y - 7)

\int \frac{d}{1} (cos (2 x)) d x