What is the derivative of y=ln(x^5) ?

The derivative of y=ln(x^5) is 5/x

What is the first derivative of y=ln(x^5) ?

The first derivative of y=ln(x^5) is 5/x

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derivative of

y = ln (x^{5})

\frac{5}{x}

Solution steps

\frac{d}{d x} (ln (x^{5}))

Apply the chain rule:

\frac{1}{x ^{5}} \frac{d}{d x} (x^{5})

= \frac{1}{x ^{5}} \frac{d}{d x} (x^{5})

\frac{d}{d x} (x^{5}) = 5 x^{4}

= \frac{1}{x ^{5}} \cdot 5 x^{4}

Simplify

\frac{1}{x ^{5}} \cdot 5 x^{4} : \frac{5}{x}

= \frac{5}{x}

\frac{d}{d x} (- \frac{3}{x ^{2}} + 4 e^{2 x})

f (x) = \frac{x ^{2}}{3}

\frac{\partial}{\partial y} (2 x + 3 y - 7)

\int \frac{d}{1} (cos (2 x)) d x

n = 1 \sum \infty (1 - p)^{3 n}

What is the derivative of y=ln(x^5) ?
The derivative of y=ln(x^5) is 5/x
What is the first derivative of y=ln(x^5) ?
The first derivative of y=ln(x^5) is 5/x