What is the sum from n=0 to infinity of (e/(6pi))^n ?

The sum from n=0 to infinity of (e/(6pi))^n is (6pi)/(6pi-e)

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sum from n=0 to infinity of (e/(6pi))^n

n = 0 \sum \infty (\frac{e}{6 π})^{n}

\frac{6 π}{6 π - e}

Decimal

1.16851 \dots

Solution steps

n = 0 \sum \infty (\frac{e}{6 π})^{n}

Apply Series Geometric Test:

\frac{6 π}{6 π - e}

= \frac{6 π}{6 π - e}

p a r t ia l f r a c t i o n \frac{x ^{2}}{1 - x}

y^{^{''}} + 3 y^{^{'}} - 10 y = 6 e^{4 x}

\int \frac{x}{x - 9} d x

x y^{2} y^{^{'}} = x^{3} + 2 y^{3}

\frac{d}{d x} (\frac{2 x}{3 x ^{2} - 3})

What is the sum from n=0 to infinity of (e/(6pi))^n ?
The sum from n=0 to infinity of (e/(6pi))^n is (6pi)/(6pi-e)